Interference Due to Thin Films

In the figure shown '$S$' is a monochromatic source of light emitting light of wavelength $\lambda$ (in air). Light falls on slit '${\mathrm{S}}_1$' from '$S$' and then reach the slits '${\mathrm{S}}_2$' and '${\mathrm{S}}_3$' 'through a medium of refractive index '${\mu }_1$'. Light from slits ${\mathrm{S}}_2$ and ${\mathrm{S}}_3$ reach the screen through medium of refractive index ${\mu }_3$. A thin transparent film of refractive index ${\mu }_2$ and thickness '$t$' is placed in front of '$S_2$'. Point '$P$' is symmetrical w.r.t. ${ \mathrm{S}}_2$ ' and '${\mathrm{S}}_3$' (Using the value $\mathrm{d}=1 \mathrm{mm},\mathrm{D}=1 \mathrm{m},{\mu }_1=4/3,{\mu }_2=3/2,{\mu }_3=9/5$ and $\mathrm{t}=\frac{4}{9}\times {10}^{-5} \mathrm{m}$ )

To find prominent diffraction , the size of diffraction object should be

When Two waves of same amplitude add constructively, the intensity becomes _____

What is the main principle used in Interference?

_____ does not show any interference pattern?

Anti-reflecting coating makes use of 

In diffraction radius of half period zone is proportional to:

As we know few currency notes change their color as you tilt then to avoid counterfeits. This is because of ________ of light.

White light reflected from a soap film (Refractive index$=1.5$) has a maxima at $600\mathrm{nm}$ and a minima at $750\mathrm{nm}$ with no minimum in between. Then the thickness of the film is _______$\times {10}^{-7}\mathrm{m}$?

How do you find the path difference between two waves?

How is the difference in paths taken by two originally in phase light waves related to whether they interfere constructively or destructively?

What is the path difference between two light waves?

What is the path difference between two light waves?

A soap film of refractive index 1.33 is illuminated by the light of wavelength at an angle of 45 degrees. There is complete destructive interference. For, find the thickness of the film.

Given Refractive index = 1.33, i = ${45}^0$

Two waves are travelling and superimposed as a result of this constructive interference occur between waves, the two waves amplitude are:

When light is incident on a soap film of thickness $5\times {10}^{-5} \mathrm{cm}$, the wavelength of light reflected maximum in the visible region is $5320 \stackrel{\circ }{\mathrm{A}}$. The refractive index of the film will be:

Interference fringes were produced in Young's double slit experiment using light of wavelength $5000 \stackrel{\circ }{\mathrm{A}}$ When a film of thickness $2.5\times {10}^{-3} \mathrm{cm}$ was placed in front of one of the slits, the fringe pattern shifted by a distance equal to $20$ fringe-widths. The refractive index of the material of the film is

InYoung's double slit experiment, a mica sheet of thickness $t$ and refractive index $\mathrm{m}$ is introduced in the path of ray from the first source ${\mathrm{S}}_1$. By how much distance the fringe pattern will be displaced :

In $YDSE$, let $A$ and $B$ be two slits as shown. Thin films of thickness $t_{\mathit{A}}$ and $t_{\mathit{B}}$ and refractive indices ${\mu }_{\mathit{A}}$ and ${\mu }_{\mathit{B}}$ are placed in front of $A$ and $B$ respectively. If ${\mu }_{\mathit{A}}{t}_{\mathit{A}}={\mu }_{\mathit{B}}{t}_{\mathit{B}}\mathit{,}$ then the central maxima will

If thickness of thin film is made extremely thin then film will appeared :-